Base | Representation |
---|---|
bin | 1100011101011101001000… |
… | …1101010111101111010101 |
3 | 1210111201112220212011200002 |
4 | 3013113102031113233111 |
5 | 3243430430410134123 |
6 | 45045435152501045 |
7 | 2612543111500121 |
oct | 307272215275725 |
9 | 53451486764602 |
10 | 13700177427413 |
11 | 4402237aa4214 |
12 | 165322984a785 |
13 | 784bc8b08299 |
14 | 355140b14581 |
15 | 18b58e0da528 |
hex | c75d2357bd5 |
13700177427413 has 2 divisors, whose sum is σ = 13700177427414. Its totient is φ = 13700177427412.
The previous prime is 13700177427379. The next prime is 13700177427551. The reversal of 13700177427413 is 31472477100731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10711697674129 + 2988479753284 = 3272873^2 + 1728722^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13700177427413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13700177427113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6850088713706 + 6850088713707.
It is an arithmetic number, because the mean of its divisors is an integer number (6850088713707).
Almost surely, 213700177427413 is an apocalyptic number.
It is an amenable number.
13700177427413 is a deficient number, since it is larger than the sum of its proper divisors (1).
13700177427413 is an equidigital number, since it uses as much as digits as its factorization.
13700177427413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691488, while the sum is 47.
The spelling of 13700177427413 in words is "thirteen trillion, seven hundred billion, one hundred seventy-seven million, four hundred twenty-seven thousand, four hundred thirteen".
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