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1370021540389 is a prime number
BaseRepresentation
bin10011111011111011101…
…001011011001000100101
311211222021011020020221221
4103323323221123020211
5134421301003243024
62525213524140341
7200660260644115
oct23737351331045
94758234206857
101370021540389
11489028496937
121a16295376b1
139c266b44388
144a448dab045
152598638d3e4
hex13efba5b225

1370021540389 has 2 divisors, whose sum is σ = 1370021540390. Its totient is φ = 1370021540388.

The previous prime is 1370021540387. The next prime is 1370021540423. The reversal of 1370021540389 is 9830451200731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1183617795364 + 186403745025 = 1087942^2 + 431745^2 .

It is a cyclic number.

It is not a de Polignac number, because 1370021540389 - 21 = 1370021540387 is a prime.

It is a super-3 number, since 3×13700215403893 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1370021540387, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1370021540387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685010770194 + 685010770195.

It is an arithmetic number, because the mean of its divisors is an integer number (685010770195).

Almost surely, 21370021540389 is an apocalyptic number.

It is an amenable number.

1370021540389 is a deficient number, since it is larger than the sum of its proper divisors (1).

1370021540389 is an equidigital number, since it uses as much as digits as its factorization.

1370021540389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 43.

The spelling of 1370021540389 in words is "one trillion, three hundred seventy billion, twenty-one million, five hundred forty thousand, three hundred eighty-nine".