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13700954190401 is a prime number
BaseRepresentation
bin1100011101100000000010…
…0000011111001001000001
31210111210120001110211011122
43013120000200133021001
53243434023233043101
645050044221322025
72612601263043212
oct307300040371101
953453501424148
1013700954190401
1144025a65037a5
121653405a06315
13784cc0a1355a
143551b5d51409
1518b5d73c251b
hexc760081f241

13700954190401 has 2 divisors, whose sum is σ = 13700954190402. Its totient is φ = 13700954190400.

The previous prime is 13700954190361. The next prime is 13700954190403. The reversal of 13700954190401 is 10409145900731.

It is a happy number.

It is a Cunningham number, because it is equal to 37014802+1.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13700954190400 + 1 = 3701480^2 + 1^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13700954190401 is a prime.

It is a super-2 number, since 2×137009541904012 (a number of 27 digits) contains 22 as substring.

Together with 13700954190403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13700954190403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6850477095200 + 6850477095201.

It is an arithmetic number, because the mean of its divisors is an integer number (6850477095201).

Almost surely, 213700954190401 is an apocalyptic number.

It is an amenable number.

13700954190401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13700954190401 is an equidigital number, since it uses as much as digits as its factorization.

13700954190401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 44.

The spelling of 13700954190401 in words is "thirteen trillion, seven hundred billion, nine hundred fifty-four million, one hundred ninety thousand, four hundred one".