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13705324153 is a prime number
BaseRepresentation
bin11001100001110011…
…01010011001111001
31022101010222121022021
430300321222121321
5211032030333103
610143544354441
7663426222163
oct146071523171
938333877267
1013705324153
1158a3330984
1227a5a75a21
1313a5556581
149402cb933
15553326bbd
hex330e6a679

13705324153 has 2 divisors, whose sum is σ = 13705324154. Its totient is φ = 13705324152.

The previous prime is 13705324151. The next prime is 13705324189. The reversal of 13705324153 is 35142350731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7252736569 + 6452587584 = 85163^2 + 80328^2 .

It is a cyclic number.

It is not a de Polignac number, because 13705324153 - 21 = 13705324151 is a prime.

Together with 13705324151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13705324151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6852662076 + 6852662077.

It is an arithmetic number, because the mean of its divisors is an integer number (6852662077).

Almost surely, 213705324153 is an apocalyptic number.

It is an amenable number.

13705324153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13705324153 is an equidigital number, since it uses as much as digits as its factorization.

13705324153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37800, while the sum is 34.

Adding to 13705324153 its reverse (35142350731), we get a palindrome (48847674884).

The spelling of 13705324153 in words is "thirteen billion, seven hundred five million, three hundred twenty-four thousand, one hundred fifty-three".