Base | Representation |
---|---|
bin | 10011111100100001111… |
… | …110111011001110111111 |
3 | 11212000220222110201022111 |
4 | 103330201332323032333 |
5 | 134424110131223403 |
6 | 2525401421354451 |
7 | 201012230545312 |
oct | 23744176731677 |
9 | 4760828421274 |
10 | 1370664711103 |
11 | 489328550586 |
12 | 1a1788a08a27 |
13 | 9c33a176a6c |
14 | 4a4aa590979 |
15 | 259c2a8756d |
hex | 13f21fbb3bf |
1370664711103 has 2 divisors, whose sum is σ = 1370664711104. Its totient is φ = 1370664711102.
The previous prime is 1370664711071. The next prime is 1370664711127. The reversal of 1370664711103 is 3011174660731.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1370664711103 - 25 = 1370664711071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1370644711103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685332355551 + 685332355552.
It is an arithmetic number, because the mean of its divisors is an integer number (685332355552).
Almost surely, 21370664711103 is an apocalyptic number.
1370664711103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1370664711103 is an equidigital number, since it uses as much as digits as its factorization.
1370664711103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63504, while the sum is 40.
The spelling of 1370664711103 in words is "one trillion, three hundred seventy billion, six hundred sixty-four million, seven hundred eleven thousand, one hundred three".
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