Base | Representation |
---|---|
bin | 10011111101001110001… |
… | …010101101111111111111 |
3 | 11212002211122100002200112 |
4 | 103331032022231333333 |
5 | 134432114414001002 |
6 | 2530003142020235 |
7 | 201036501443642 |
oct | 23751612557777 |
9 | 4762748302615 |
10 | 1371406000127 |
11 | 489678a30a39 |
12 | 1a195511767b |
13 | 9c427911617 |
14 | 4a53abd5a59 |
15 | 25a17bb3852 |
hex | 13f4e2adfff |
1371406000127 has 2 divisors, whose sum is σ = 1371406000128. Its totient is φ = 1371406000126.
The previous prime is 1371406000039. The next prime is 1371406000169. The reversal of 1371406000127 is 7210006041731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1371406000127 - 28 = 1371405999871 is a prime.
It is a super-2 number, since 2×13714060001272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1371406000093 and 1371406000102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1371406000187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685703000063 + 685703000064.
It is an arithmetic number, because the mean of its divisors is an integer number (685703000064).
Almost surely, 21371406000127 is an apocalyptic number.
1371406000127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371406000127 is an equidigital number, since it uses as much as digits as its factorization.
1371406000127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7056, while the sum is 32.
The spelling of 1371406000127 in words is "one trillion, three hundred seventy-one billion, four hundred six million, one hundred twenty-seven", and thus it is an aban number.
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