Base | Representation |
---|---|
bin | 10011111110000001101… |
… | …011011001011000000101 |
3 | 11212012001212111020002222 |
4 | 103332001223121120011 |
5 | 134440402133020141 |
6 | 2530225012542125 |
7 | 201100064164664 |
oct | 23760153313005 |
9 | 4765055436088 |
10 | 1372270204421 |
11 | 489a81834466 |
12 | 1a1b56621945 |
13 | 9c534983ccc |
14 | 4a5bd8b4ddb |
15 | 25a689be14b |
hex | 13f81ad9605 |
1372270204421 has 2 divisors, whose sum is σ = 1372270204422. Its totient is φ = 1372270204420.
The previous prime is 1372270204309. The next prime is 1372270204423. The reversal of 1372270204421 is 1244020722731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1192112401921 + 180157802500 = 1091839^2 + 424450^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1372270204421 is a prime.
Together with 1372270204423, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1372270204423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 686135102210 + 686135102211.
It is an arithmetic number, because the mean of its divisors is an integer number (686135102211).
Almost surely, 21372270204421 is an apocalyptic number.
It is an amenable number.
1372270204421 is a deficient number, since it is larger than the sum of its proper divisors (1).
1372270204421 is an equidigital number, since it uses as much as digits as its factorization.
1372270204421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37632, while the sum is 35.
The spelling of 1372270204421 in words is "one trillion, three hundred seventy-two billion, two hundred seventy million, two hundred four thousand, four hundred twenty-one".
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