Base | Representation |
---|---|
bin | 10011111110000101111… |
… | …111010100110101000101 |
3 | 11212012020220121010111102 |
4 | 103332011333110311011 |
5 | 134441024142200131 |
6 | 2530240115145445 |
7 | 201101633046503 |
oct | 23760577246505 |
9 | 4765226533442 |
10 | 1372342537541 |
11 | 48a0096493a8 |
12 | 1a1b768a5285 |
13 | 9c54695b781 |
14 | 4a5c9343673 |
15 | 25a7000b1cb |
hex | 13f85fd4d45 |
1372342537541 has 2 divisors, whose sum is σ = 1372342537542. Its totient is φ = 1372342537540.
The previous prime is 1372342537499. The next prime is 1372342537679. The reversal of 1372342537541 is 1457352432731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1354186053025 + 18156484516 = 1163695^2 + 134746^2 .
It is a cyclic number.
It is not a de Polignac number, because 1372342537541 - 218 = 1372342275397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1372347537541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 686171268770 + 686171268771.
It is an arithmetic number, because the mean of its divisors is an integer number (686171268771).
Almost surely, 21372342537541 is an apocalyptic number.
It is an amenable number.
1372342537541 is a deficient number, since it is larger than the sum of its proper divisors (1).
1372342537541 is an equidigital number, since it uses as much as digits as its factorization.
1372342537541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2116800, while the sum is 47.
The spelling of 1372342537541 in words is "one trillion, three hundred seventy-two billion, three hundred forty-two million, five hundred thirty-seven thousand, five hundred forty-one".
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