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137239439 is a prime number
BaseRepresentation
bin10000010111000…
…01101110001111
3100120020111010012
420023201232033
5240113130224
621341303435
73254341661
oct1013415617
9316214105
10137239439
1170517027
1239b64b7b
132258198c
1414326531
15c0ad80e
hex82e1b8f

137239439 has 2 divisors, whose sum is σ = 137239440. Its totient is φ = 137239438.

The previous prime is 137239381. The next prime is 137239441. The reversal of 137239439 is 934932731.

137239439 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-137239439 is a prime.

Together with 137239441, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 137239396 and 137239405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137239469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68619719 + 68619720.

It is an arithmetic number, because the mean of its divisors is an integer number (68619720).

Almost surely, 2137239439 is an apocalyptic number.

137239439 is a deficient number, since it is larger than the sum of its proper divisors (1).

137239439 is an equidigital number, since it uses as much as digits as its factorization.

137239439 is an evil number, because the sum of its binary digits is even.

The product of its digits is 122472, while the sum is 41.

The square root of 137239439 is about 11714.9237726927. The cubic root of 137239439 is about 515.8138249792.

The spelling of 137239439 in words is "one hundred thirty-seven million, two hundred thirty-nine thousand, four hundred thirty-nine".