Base | Representation |
---|---|
bin | 111111111010011110… |
… | …0000010001111111101 |
3 | 111010021102102100111002 |
4 | 1333310330002033331 |
5 | 4222043330132413 |
6 | 143015303540045 |
7 | 12626160231212 |
oct | 1776474021775 |
9 | 433242370432 |
10 | 137253364733 |
11 | 53232a45441 |
12 | 22725a5a625 |
13 | cc3482a824 |
14 | 6900939b09 |
15 | 3884a28958 |
hex | 1ff4f023fd |
137253364733 has 2 divisors, whose sum is σ = 137253364734. Its totient is φ = 137253364732.
The previous prime is 137253364691. The next prime is 137253364741. The reversal of 137253364733 is 337463352731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130987534084 + 6265830649 = 361922^2 + 79157^2 .
It is a cyclic number.
It is not a de Polignac number, because 137253364733 - 224 = 137236587517 is a prime.
It is a super-2 number, since 2×1372533647332 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (137253364433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68626682366 + 68626682367.
It is an arithmetic number, because the mean of its divisors is an integer number (68626682367).
Almost surely, 2137253364733 is an apocalyptic number.
It is an amenable number.
137253364733 is a deficient number, since it is larger than the sum of its proper divisors (1).
137253364733 is an equidigital number, since it uses as much as digits as its factorization.
137253364733 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2857680, while the sum is 47.
The spelling of 137253364733 in words is "one hundred thirty-seven billion, two hundred fifty-three million, three hundred sixty-four thousand, seven hundred thirty-three".
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