Base | Representation |
---|---|
bin | 11001100110000110… |
… | …00101001011011111 |
3 | 1022110122202210010012 |
4 | 30303003011023133 |
5 | 211120241110201 |
6 | 10151312433435 |
7 | 664344345521 |
oct | 146303051337 |
9 | 38418683105 |
10 | 13741347551 |
11 | 59116a5888 |
12 | 27b5b4887b |
13 | 13acb5a0a9 |
14 | 944dc7a11 |
15 | 5565905bb |
hex | 3330c52df |
13741347551 has 2 divisors, whose sum is σ = 13741347552. Its totient is φ = 13741347550.
The previous prime is 13741347533. The next prime is 13741347553. The reversal of 13741347551 is 15574314731.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13741347551 is a prime.
Together with 13741347553, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13741347499 and 13741347508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13741347553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6870673775 + 6870673776.
It is an arithmetic number, because the mean of its divisors is an integer number (6870673776).
Almost surely, 213741347551 is an apocalyptic number.
13741347551 is a deficient number, since it is larger than the sum of its proper divisors (1).
13741347551 is an equidigital number, since it uses as much as digits as its factorization.
13741347551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 176400, while the sum is 41.
The spelling of 13741347551 in words is "thirteen billion, seven hundred forty-one million, three hundred forty-seven thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •