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1374413147 is a prime number
BaseRepresentation
bin101000111101011…
…1110000101011011
310112210012102101122
41101322332011123
510303322210042
6344214235455
746026214262
oct12172760533
93483172348
101374413147
11645902a38
12324355b8b
1318b990423
14d07715d9
15809dd7d2
hex51ebe15b

1374413147 has 2 divisors, whose sum is σ = 1374413148. Its totient is φ = 1374413146.

The previous prime is 1374413141. The next prime is 1374413149. The reversal of 1374413147 is 7413144731.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1374413147 - 28 = 1374412891 is a prime.

It is a super-2 number, since 2×13744131472 = 3778022997292887218, which contains 22 as substring.

Together with 1374413149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1374413141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 687206573 + 687206574.

It is an arithmetic number, because the mean of its divisors is an integer number (687206574).

Almost surely, 21374413147 is an apocalyptic number.

1374413147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1374413147 is an equidigital number, since it uses as much as digits as its factorization.

1374413147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 28224, while the sum is 35.

The square root of 1374413147 is about 37073.0784667257. The cubic root of 1374413147 is about 1111.8318228468.

Adding to 1374413147 its reverse (7413144731), we get a palindrome (8787557878).

The spelling of 1374413147 in words is "one billion, three hundred seventy-four million, four hundred thirteen thousand, one hundred forty-seven".