Base | Representation |
---|---|
bin | 11001100111100111… |
… | …11001011011010111 |
3 | 1022111112211221012012 |
4 | 30303303321123113 |
5 | 211132030110341 |
6 | 10152451014435 |
7 | 664561204364 |
oct | 146363713327 |
9 | 38445757165 |
10 | 13754144471 |
11 | 5918946351 |
12 | 27ba29a41b |
13 | 13b26baa32 |
14 | 94699946b |
15 | 55776c0eb |
hex | 333cf96d7 |
13754144471 has 2 divisors, whose sum is σ = 13754144472. Its totient is φ = 13754144470.
The previous prime is 13754144413. The next prime is 13754144473. The reversal of 13754144471 is 17444145731.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13754144471 is a prime.
It is a super-3 number, since 3×137541444713 (a number of 31 digits) contains 333 as substring.
Together with 13754144473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13754144473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6877072235 + 6877072236.
It is an arithmetic number, because the mean of its divisors is an integer number (6877072236).
Almost surely, 213754144471 is an apocalyptic number.
13754144471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13754144471 is an equidigital number, since it uses as much as digits as its factorization.
13754144471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 188160, while the sum is 41.
The spelling of 13754144471 in words is "thirteen billion, seven hundred fifty-four million, one hundred forty-four thousand, four hundred seventy-one".
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