Base | Representation |
---|---|
bin | 10100000001000010001… |
… | …111100111010101000011 |
3 | 11212111102000122210112002 |
4 | 110001002033213111003 |
5 | 140014011214033402 |
6 | 2531521342254215 |
7 | 201243123642113 |
oct | 24010217472503 |
9 | 4774360583462 |
10 | 1375500924227 |
11 | 49038a45a031 |
12 | 1a26b858736b |
13 | 9c92b0ba331 |
14 | 4a8089b9043 |
15 | 25ba7439602 |
hex | 140423e7543 |
1375500924227 has 2 divisors, whose sum is σ = 1375500924228. Its totient is φ = 1375500924226.
The previous prime is 1375500924221. The next prime is 1375500924229. The reversal of 1375500924227 is 7224290055731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1375500924227 - 214 = 1375500907843 is a prime.
Together with 1375500924229, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1375500924221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 687750462113 + 687750462114.
It is an arithmetic number, because the mean of its divisors is an integer number (687750462114).
Almost surely, 21375500924227 is an apocalyptic number.
1375500924227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1375500924227 is an equidigital number, since it uses as much as digits as its factorization.
1375500924227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1058400, while the sum is 47.
Adding to 1375500924227 its reverse (7224290055731), we get a palindrome (8599790979958).
The spelling of 1375500924227 in words is "one trillion, three hundred seventy-five billion, five hundred million, nine hundred twenty-four thousand, two hundred twenty-seven".
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