Base | Representation |
---|---|
bin | 1100100010000111011011… |
… | …1011011010110000010111 |
3 | 1210210101020100020021101202 |
4 | 3020201312323122300113 |
5 | 3301233423043420033 |
6 | 45150320513543115 |
7 | 2621406310344362 |
oct | 310416673326027 |
9 | 53711210207352 |
10 | 13780250373143 |
11 | 44331980a3521 |
12 | 1666855b74a9b |
13 | 78c61a0a0647 |
14 | 358d7943b0d9 |
15 | 18d6c8bb78e8 |
hex | c8876edac17 |
13780250373143 has 2 divisors, whose sum is σ = 13780250373144. Its totient is φ = 13780250373142.
The previous prime is 13780250373067. The next prime is 13780250373163. The reversal of 13780250373143 is 34137305208731.
It is a strong prime.
It is an emirp because it is prime and its reverse (34137305208731) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13780250373143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13780250373163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6890125186571 + 6890125186572.
It is an arithmetic number, because the mean of its divisors is an integer number (6890125186572).
Almost surely, 213780250373143 is an apocalyptic number.
13780250373143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13780250373143 is an equidigital number, since it uses as much as digits as its factorization.
13780250373143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1270080, while the sum is 47.
The spelling of 13780250373143 in words is "thirteen trillion, seven hundred eighty billion, two hundred fifty million, three hundred seventy-three thousand, one hundred forty-three".
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