Base | Representation |
---|---|
bin | 11001101100011011… |
… | …10101000011010000 |
3 | 1022121100210001001221 |
4 | 30312031311003100 |
5 | 211222342343340 |
6 | 10200451534424 |
7 | 665561200414 |
oct | 146615650320 |
9 | 38540701057 |
10 | 13794496720 |
11 | 59396a7614 |
12 | 280b8ba414 |
13 | 13bab789c4 |
14 | 94c0a0d44 |
15 | 55b08d44a |
hex | 3363750d0 |
13794496720 has 20 divisors (see below), whose sum is σ = 32072205060. Its totient is φ = 5517798656.
The previous prime is 13794496693. The next prime is 13794496739. The reversal of 13794496720 is 2769449731.
It can be written as a sum of positive squares in 2 ways, for example, as 3785694784 + 10008801936 = 61528^2 + 100044^2 .
It is a tau number, because it is divible by the number of its divisors (20).
It is a super-3 number, since 3×137944967203 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86215525 + ... + 86215684.
It is an arithmetic number, because the mean of its divisors is an integer number (1603610253).
Almost surely, 213794496720 is an apocalyptic number.
13794496720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13794496720 is an abundant number, since it is smaller than the sum of its proper divisors (18277708340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13794496720 is a wasteful number, since it uses less digits than its factorization.
13794496720 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172431222 (or 172431216 counting only the distinct ones).
The product of its (nonzero) digits is 2286144, while the sum is 52.
The spelling of 13794496720 in words is "thirteen billion, seven hundred ninety-four million, four hundred ninety-six thousand, seven hundred twenty".
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