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1379725130437 is a prime number
BaseRepresentation
bin10100000100111110000…
…001101011101011000101
311212220022102020201001221
4110010332001223223011
5140101134113133222
62533500441520341
7201452606051113
oct24047601535305
94786272221057
101379725130437
11492157959745
121a34971a30b1
13a01522bcb34
144aac9a12ab3
1525d531eb0c7
hex1413e06bac5

1379725130437 has 2 divisors, whose sum is σ = 1379725130438. Its totient is φ = 1379725130436.

The previous prime is 1379725130431. The next prime is 1379725130501. The reversal of 1379725130437 is 7340315279731.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1274480687041 + 105244443396 = 1128929^2 + 324414^2 .

It is a cyclic number.

It is not a de Polignac number, because 1379725130437 - 23 = 1379725130429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1379725130431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 689862565218 + 689862565219.

It is an arithmetic number, because the mean of its divisors is an integer number (689862565219).

Almost surely, 21379725130437 is an apocalyptic number.

It is an amenable number.

1379725130437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1379725130437 is an equidigital number, since it uses as much as digits as its factorization.

1379725130437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3333960, while the sum is 52.

The spelling of 1379725130437 in words is "one trillion, three hundred seventy-nine billion, seven hundred twenty-five million, one hundred thirty thousand, four hundred thirty-seven".