Base | Representation |
---|---|
bin | 1100100011010010110101… |
… | …1010011101010010010110 |
3 | 1210212022111000002221120112 |
4 | 3020310231122131102112 |
5 | 3302101401402114340 |
6 | 45203505230403022 |
7 | 2623024024042340 |
oct | 310645532352226 |
9 | 53768430087515 |
10 | 13800491832470 |
11 | 4440834952502 |
12 | 166a764960472 |
13 | 7914c47ba405 |
14 | 359d39818290 |
15 | 18deb0c2c065 |
hex | c8d2d69d496 |
13800491832470 has 32 divisors (see below), whose sum is σ = 28390105387008. Its totient is φ = 4731510168288.
The previous prime is 13800491832461. The next prime is 13800491832499. The reversal of 13800491832470 is 7423819400831.
13800491832470 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2078939 + ... + 5650041.
It is an arithmetic number, because the mean of its divisors is an integer number (887190793344).
Almost surely, 213800491832470 is an apocalyptic number.
13800491832470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13800491832470 is an abundant number, since it is smaller than the sum of its proper divisors (14589613554538).
13800491832470 is a wasteful number, since it uses less digits than its factorization.
13800491832470 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3626324.
The product of its (nonzero) digits is 1161216, while the sum is 50.
The spelling of 13800491832470 in words is "thirteen trillion, eight hundred billion, four hundred ninety-one million, eight hundred thirty-two thousand, four hundred seventy".
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