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1380113143 is a prime number
BaseRepresentation
bin101001001000010…
…1101101011110111
310120011221000022121
41102100231223313
510311302110033
6344540340411
746125524323
oct12220555367
93504830277
101380113143
11649046482
12326244707
1318cc079c6
14d1416983
158126762d
hex5242daf7

1380113143 has 2 divisors, whose sum is σ = 1380113144. Its totient is φ = 1380113142.

The previous prime is 1380113129. The next prime is 1380113153. The reversal of 1380113143 is 3413110831.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1380113143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1380113153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690056571 + 690056572.

It is an arithmetic number, because the mean of its divisors is an integer number (690056572).

Almost surely, 21380113143 is an apocalyptic number.

1380113143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1380113143 is an equidigital number, since it uses as much as digits as its factorization.

1380113143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 25.

The square root of 1380113143 is about 37149.8740643895. The cubic root of 1380113143 is about 1113.3667073095.

Adding to 1380113143 its reverse (3413110831), we get a palindrome (4793223974).

The spelling of 1380113143 in words is "one billion, three hundred eighty million, one hundred thirteen thousand, one hundred forty-three".