Base | Representation |
---|---|
bin | 10100000101110011011… |
… | …101110101111000001101 |
3 | 11212222121220022101202202 |
4 | 110011303131311320031 |
5 | 140110003124022332 |
6 | 2534125430331245 |
7 | 201514043601233 |
oct | 24056335657015 |
9 | 4788556271682 |
10 | 1380621704717 |
11 | 492577a61222 |
12 | 1a36a74b9b25 |
13 | a0265c87168 |
14 | 4ab72b1a953 |
15 | 25da6c9ca62 |
hex | 14173775e0d |
1380621704717 has 2 divisors, whose sum is σ = 1380621704718. Its totient is φ = 1380621704716.
The previous prime is 1380621704687. The next prime is 1380621704723. The reversal of 1380621704717 is 7174071260831.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1111462039081 + 269159665636 = 1054259^2 + 518806^2 .
It is a cyclic number.
It is not a de Polignac number, because 1380621704717 - 210 = 1380621703693 is a prime.
It is a super-2 number, since 2×13806217047172 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1380621704017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690310852358 + 690310852359.
It is an arithmetic number, because the mean of its divisors is an integer number (690310852359).
Almost surely, 21380621704717 is an apocalyptic number.
It is an amenable number.
1380621704717 is a deficient number, since it is larger than the sum of its proper divisors (1).
1380621704717 is an equidigital number, since it uses as much as digits as its factorization.
1380621704717 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 395136, while the sum is 47.
The spelling of 1380621704717 in words is "one trillion, three hundred eighty billion, six hundred twenty-one million, seven hundred four thousand, seven hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •