Base | Representation |
---|---|
bin | 11111011001010101000111… |
… | …110001010101001110111110 |
3 | 200002220022220010012011201212 |
4 | 133121111013301111032332 |
5 | 121044301030033312340 |
6 | 1205401043100204422 |
7 | 41040646535102036 |
oct | 3731250761251676 |
9 | 602808803164655 |
10 | 138080107713470 |
11 | 3aaa649907723a |
12 | 135a0a24839712 |
13 | 5c07b8a6c5820 |
14 | 2615181a148c6 |
15 | 10e6ba91a7a65 |
hex | 7d9547c553be |
138080107713470 has 64 divisors (see below), whose sum is σ = 269501832827136. Its totient is φ = 50634343710720.
The previous prime is 138080107713463. The next prime is 138080107713511. The reversal of 138080107713470 is 74317701080831.
It is a super-2 number, since 2×1380801077134702 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5127275 + ... + 17391065.
It is an arithmetic number, because the mean of its divisors is an integer number (4210966137924).
Almost surely, 2138080107713470 is an apocalyptic number.
138080107713470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
138080107713470 is a deficient number, since it is larger than the sum of its proper divisors (131421725113666).
138080107713470 is a wasteful number, since it uses less digits than its factorization.
138080107713470 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12264405.
The product of its (nonzero) digits is 790272, while the sum is 50.
The spelling of 138080107713470 in words is "one hundred thirty-eight trillion, eighty billion, one hundred seven million, seven hundred thirteen thousand, four hundred seventy".
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