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13810064381 is a prime number
BaseRepresentation
bin11001101110010010…
…01101101111111101
31022122110001221212222
430313021031233331
5211240334030011
610202205335125
7666140416241
oct146711155775
938573057788
1013810064381
11594746a853
122814b674a5
1313c1169839
14950194421
1555c615ddb
hex33724dbfd

13810064381 has 2 divisors, whose sum is σ = 13810064382. Its totient is φ = 13810064380.

The previous prime is 13810064377. The next prime is 13810064383. The reversal of 13810064381 is 18346001831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7071296281 + 6738768100 = 84091^2 + 82090^2 .

It is a cyclic number.

It is not a de Polignac number, because 13810064381 - 22 = 13810064377 is a prime.

It is a super-2 number, since 2×138100643812 (a number of 21 digits) contains 22 as substring.

Together with 13810064383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13810064383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6905032190 + 6905032191.

It is an arithmetic number, because the mean of its divisors is an integer number (6905032191).

Almost surely, 213810064381 is an apocalyptic number.

It is an amenable number.

13810064381 is a deficient number, since it is larger than the sum of its proper divisors (1).

13810064381 is an equidigital number, since it uses as much as digits as its factorization.

13810064381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 35.

The spelling of 13810064381 in words is "thirteen billion, eight hundred ten million, sixty-four thousand, three hundred eighty-one".