Base | Representation |
---|---|
bin | 11001101111111101… |
… | …00000111101010001 |
3 | 1022200102100211021212 |
4 | 30313332200331101 |
5 | 211302423133224 |
6 | 10203425025505 |
7 | 666400241651 |
oct | 146776407521 |
9 | 38612324255 |
10 | 13824036689 |
11 | 5954343411 |
12 | 2819785295 |
13 | 13c401c488 |
14 | 951d90361 |
15 | 55d975d0e |
hex | 337fa0f51 |
13824036689 has 2 divisors, whose sum is σ = 13824036690. Its totient is φ = 13824036688.
The previous prime is 13824036671. The next prime is 13824036691. The reversal of 13824036689 is 98663042831.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13814476225 + 9560464 = 117535^2 + 3092^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13824036689 is a prime.
It is a super-2 number, since 2×138240366892 (a number of 21 digits) contains 22 as substring.
Together with 13824036691, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13824036619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6912018344 + 6912018345.
It is an arithmetic number, because the mean of its divisors is an integer number (6912018345).
Almost surely, 213824036689 is an apocalyptic number.
It is an amenable number.
13824036689 is a deficient number, since it is larger than the sum of its proper divisors (1).
13824036689 is an equidigital number, since it uses as much as digits as its factorization.
13824036689 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1492992, while the sum is 50.
The spelling of 13824036689 in words is "thirteen billion, eight hundred twenty-four million, thirty-six thousand, six hundred eighty-nine".
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