Search a number
-
+
13839920453 is a prime number
BaseRepresentation
bin11001110001110110…
…00110110101000101
31022201112020210201102
430320323012311011
5211321004423303
610205153305445
7666652245212
oct147073066505
938645223642
1013839920453
115962302097
122822b65285
1313c73c1158
14954126b09
15560062288
hex338ec6d45

13839920453 has 2 divisors, whose sum is σ = 13839920454. Its totient is φ = 13839920452.

The previous prime is 13839920443. The next prime is 13839920477. The reversal of 13839920453 is 35402993831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11526599044 + 2313321409 = 107362^2 + 48097^2 .

It is a cyclic number.

It is not a de Polignac number, because 13839920453 - 212 = 13839916357 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13839920398 and 13839920407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13839920443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6919960226 + 6919960227.

It is an arithmetic number, because the mean of its divisors is an integer number (6919960227).

Almost surely, 213839920453 is an apocalyptic number.

It is an amenable number.

13839920453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13839920453 is an equidigital number, since it uses as much as digits as its factorization.

13839920453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 699840, while the sum is 47.

The spelling of 13839920453 in words is "thirteen billion, eight hundred thirty-nine million, nine hundred twenty thousand, four hundred fifty-three".