Base | Representation |
---|---|
bin | 1100100101101111010101… |
… | …0101010011100110100111 |
3 | 1211000022220200002000112202 |
4 | 3021123311111103212213 |
5 | 3303243420130142301 |
6 | 45235053525005115 |
7 | 2626042032661436 |
oct | 311336525234647 |
9 | 54008820060482 |
10 | 13842500630951 |
11 | 4457631807583 |
12 | 167692955379b |
13 | 79545aaa7a15 |
14 | 35bda2ad111d |
15 | 19011dc6366b |
hex | c96f55539a7 |
13842500630951 has 2 divisors, whose sum is σ = 13842500630952. Its totient is φ = 13842500630950.
The previous prime is 13842500630897. The next prime is 13842500631083. The reversal of 13842500630951 is 15903600524831.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13842500630951 - 214 = 13842500614567 is a prime.
It is a super-2 number, since 2×138425006309512 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13842500630896 and 13842500630905.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13842500630051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6921250315475 + 6921250315476.
It is an arithmetic number, because the mean of its divisors is an integer number (6921250315476).
Almost surely, 213842500630951 is an apocalyptic number.
13842500630951 is a deficient number, since it is larger than the sum of its proper divisors (1).
13842500630951 is an equidigital number, since it uses as much as digits as its factorization.
13842500630951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 777600, while the sum is 47.
The spelling of 13842500630951 in words is "thirteen trillion, eight hundred forty-two billion, five hundred million, six hundred thirty thousand, nine hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •