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138541756119929 is a prime number
BaseRepresentation
bin11111100000000011000100…
…001010001111101101111001
3200011112110111012010002000222
4133200003010022033231321
5121124332004031314204
61210353112031505425
741116211603600351
oct3740030412175571
9604473435102028
10138541756119929
114016425760a888
12136563a1988275
135c3c57c144a86
14262d657561b61
151103bc7db5abe
hex7e00c428fb79

138541756119929 has 2 divisors, whose sum is σ = 138541756119930. Its totient is φ = 138541756119928.

The previous prime is 138541756119913. The next prime is 138541756119931. The reversal of 138541756119929 is 929911657145831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 137487889623529 + 1053866496400 = 11725523^2 + 1026580^2 .

It is a cyclic number.

It is not a de Polignac number, because 138541756119929 - 24 = 138541756119913 is a prime.

Together with 138541756119931, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (138541756119829) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69270878059964 + 69270878059965.

It is an arithmetic number, because the mean of its divisors is an integer number (69270878059965).

Almost surely, 2138541756119929 is an apocalyptic number.

It is an amenable number.

138541756119929 is a deficient number, since it is larger than the sum of its proper divisors (1).

138541756119929 is an equidigital number, since it uses as much as digits as its factorization.

138541756119929 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 146966400, while the sum is 71.

The spelling of 138541756119929 in words is "one hundred thirty-eight trillion, five hundred forty-one billion, seven hundred fifty-six million, one hundred nineteen thousand, nine hundred twenty-nine".