Base | Representation |
---|---|
bin | 11111100000000011000100… |
… | …001010001111101101101001 |
3 | 200011112110111012010002000101 |
4 | 133200003010022033231221 |
5 | 121124332004031314123 |
6 | 1210353112031505401 |
7 | 41116211603600326 |
oct | 3740030412175551 |
9 | 604473435102011 |
10 | 138541756119913 |
11 | 4016425760a873 |
12 | 136563a1988261 |
13 | 5c3c57c144a73 |
14 | 262d657561b4d |
15 | 1103bc7db5aad |
hex | 7e00c428fb69 |
138541756119913 has 2 divisors, whose sum is σ = 138541756119914. Its totient is φ = 138541756119912.
The previous prime is 138541756119911. The next prime is 138541756119929. The reversal of 138541756119913 is 319911657145831.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 136481460470784 + 2060295649129 = 11682528^2 + 1435373^2 .
It is a cyclic number.
It is not a de Polignac number, because 138541756119913 - 21 = 138541756119911 is a prime.
Together with 138541756119911, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (138541756119911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69270878059956 + 69270878059957.
It is an arithmetic number, because the mean of its divisors is an integer number (69270878059957).
Almost surely, 2138541756119913 is an apocalyptic number.
It is an amenable number.
138541756119913 is a deficient number, since it is larger than the sum of its proper divisors (1).
138541756119913 is an equidigital number, since it uses as much as digits as its factorization.
138541756119913 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24494400, while the sum is 64.
The spelling of 138541756119913 in words is "one hundred thirty-eight trillion, five hundred forty-one billion, seven hundred fifty-six million, one hundred nineteen thousand, nine hundred thirteen".
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