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138541756119913 is a prime number
BaseRepresentation
bin11111100000000011000100…
…001010001111101101101001
3200011112110111012010002000101
4133200003010022033231221
5121124332004031314123
61210353112031505401
741116211603600326
oct3740030412175551
9604473435102011
10138541756119913
114016425760a873
12136563a1988261
135c3c57c144a73
14262d657561b4d
151103bc7db5aad
hex7e00c428fb69

138541756119913 has 2 divisors, whose sum is σ = 138541756119914. Its totient is φ = 138541756119912.

The previous prime is 138541756119911. The next prime is 138541756119929. The reversal of 138541756119913 is 319911657145831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 136481460470784 + 2060295649129 = 11682528^2 + 1435373^2 .

It is a cyclic number.

It is not a de Polignac number, because 138541756119913 - 21 = 138541756119911 is a prime.

Together with 138541756119911, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (138541756119911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69270878059956 + 69270878059957.

It is an arithmetic number, because the mean of its divisors is an integer number (69270878059957).

Almost surely, 2138541756119913 is an apocalyptic number.

It is an amenable number.

138541756119913 is a deficient number, since it is larger than the sum of its proper divisors (1).

138541756119913 is an equidigital number, since it uses as much as digits as its factorization.

138541756119913 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24494400, while the sum is 64.

The spelling of 138541756119913 in words is "one hundred thirty-eight trillion, five hundred forty-one billion, seven hundred fifty-six million, one hundred nineteen thousand, nine hundred thirteen".