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138637656253 is a prime number
BaseRepresentation
bin1000000100011101110…
…0101100000010111101
3111020211220012122110101
42001013130230002331
54232412220000003
6143404514041101
713005366430435
oct2010734540275
9436756178411
10138637656253
1153883385118
1222a51579191
13100c5569335
1469d271d2c5
15391631911d
hex204772c0bd

138637656253 has 2 divisors, whose sum is σ = 138637656254. Its totient is φ = 138637656252.

The previous prime is 138637656251. The next prime is 138637656341. The reversal of 138637656253 is 352656736831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134921778489 + 3715877764 = 367317^2 + 60958^2 .

It is a cyclic number.

It is not a de Polignac number, because 138637656253 - 21 = 138637656251 is a prime.

Together with 138637656251, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 138637656194 and 138637656203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (138637656251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69318828126 + 69318828127.

It is an arithmetic number, because the mean of its divisors is an integer number (69318828127).

Almost surely, 2138637656253 is an apocalyptic number.

It is an amenable number.

138637656253 is a deficient number, since it is larger than the sum of its proper divisors (1).

138637656253 is an equidigital number, since it uses as much as digits as its factorization.

138637656253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16329600, while the sum is 55.

The spelling of 138637656253 in words is "one hundred thirty-eight billion, six hundred thirty-seven million, six hundred fifty-six thousand, two hundred fifty-three".