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138784167233263 is a prime number
BaseRepresentation
bin11111100011100100110100…
…111111010000011011101111
3200012101122012020101112201201
4133203210310333100123233
5121142314433302431023
61211100322151150331
741142553020216166
oct3743446477203357
9605348166345651
10138784167233263
1140248042342172
12136953749753a7
135c593a1bc3686
14263b2921243dd
15110a164840bad
hex7e3934fd06ef

138784167233263 has 2 divisors, whose sum is σ = 138784167233264. Its totient is φ = 138784167233262.

The previous prime is 138784167233221. The next prime is 138784167233273. The reversal of 138784167233263 is 362332761487831.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-138784167233263 is a prime.

It is a super-2 number, since 2×1387841672332632 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 138784167233195 and 138784167233204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (138784167233273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69392083616631 + 69392083616632.

It is an arithmetic number, because the mean of its divisors is an integer number (69392083616632).

Almost surely, 2138784167233263 is an apocalyptic number.

138784167233263 is a deficient number, since it is larger than the sum of its proper divisors (1).

138784167233263 is an equidigital number, since it uses as much as digits as its factorization.

138784167233263 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 146313216, while the sum is 64.

The spelling of 138784167233263 in words is "one hundred thirty-eight trillion, seven hundred eighty-four billion, one hundred sixty-seven million, two hundred thirty-three thousand, two hundred sixty-three".