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13879725105887 is a prime number
BaseRepresentation
bin1100100111111010000000…
…0101011010001011011111
31211010212222220111021102122
43021332200011122023133
53304401134111342022
645304131354413155
72631530345541434
oct311764005321337
954125886437378
1013879725105887
1144713a3a84553
121681b97a311bb
13798b10b1c254
1435dad4809b8b
1519109bc47742
hexc9fa015a2df

13879725105887 has 2 divisors, whose sum is σ = 13879725105888. Its totient is φ = 13879725105886.

The previous prime is 13879725105839. The next prime is 13879725105889. The reversal of 13879725105887 is 78850152797831.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13879725105887 - 26 = 13879725105823 is a prime.

Together with 13879725105889, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13879725105887.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13879725105889) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6939862552943 + 6939862552944.

It is an arithmetic number, because the mean of its divisors is an integer number (6939862552944).

Almost surely, 213879725105887 is an apocalyptic number.

13879725105887 is a deficient number, since it is larger than the sum of its proper divisors (1).

13879725105887 is an equidigital number, since it uses as much as digits as its factorization.

13879725105887 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 237081600, while the sum is 71.

The spelling of 13879725105887 in words is "thirteen trillion, eight hundred seventy-nine billion, seven hundred twenty-five million, one hundred five thousand, eight hundred eighty-seven".