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139102631364320 = 25513247793074513
BaseRepresentation
bin11111101000001101011010…
…111011100000011011100000
3200020112002012112211121121122
4133220031122323200123200
5121213024142112124240
61211502511110511412
741204555610526451
oct3750153273403340
9606462175747548
10139102631364320
1140360105009408
1213727031965568
135c80425159500
14264c86358d128
1511135a2ed84b5
hex7e835aee06e0

139102631364320 has 576 divisors, whose sum is σ = 369306018385920. Its totient is φ = 49459249741824.

The previous prime is 139102631364311. The next prime is 139102631364373. The reversal of 139102631364320 is 23463136201931.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 30822650384 + ... + 30822654896.

It is an arithmetic number, because the mean of its divisors is an integer number (641156281920).

Almost surely, 2139102631364320 is an apocalyptic number.

139102631364320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 139102631364320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184653009192960).

139102631364320 is an abundant number, since it is smaller than the sum of its proper divisors (230203387021600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

139102631364320 is a wasteful number, since it uses less digits than its factorization.

139102631364320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4987 (or 4966 counting only the distinct ones).

The product of its (nonzero) digits is 419904, while the sum is 44.

The spelling of 139102631364320 in words is "one hundred thirty-nine trillion, one hundred two billion, six hundred thirty-one million, three hundred sixty-four thousand, three hundred twenty".