Base | Representation |
---|---|
bin | 1100101010010101111111… |
… | …0101101011001010010101 |
3 | 1211021220002000200102120201 |
4 | 3022211133311223022111 |
5 | 3311042412302143102 |
6 | 45335254320500501 |
7 | 2634542102165635 |
oct | 312453765531225 |
9 | 54256060612521 |
10 | 13921596912277 |
11 | 448813058141a |
12 | 168a12277a731 |
13 | 79ca54913652 |
14 | 361b478226c5 |
15 | 1921ecc1d987 |
hex | ca95fd6b295 |
13921596912277 has 2 divisors, whose sum is σ = 13921596912278. Its totient is φ = 13921596912276.
The previous prime is 13921596912257. The next prime is 13921596912299. The reversal of 13921596912277 is 77221969512931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10904518235601 + 3017078676676 = 3302199^2 + 1736974^2 .
It is a cyclic number.
It is not a de Polignac number, because 13921596912277 - 231 = 13919449428629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13921596912227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6960798456138 + 6960798456139.
It is an arithmetic number, because the mean of its divisors is an integer number (6960798456139).
Almost surely, 213921596912277 is an apocalyptic number.
It is an amenable number.
13921596912277 is a deficient number, since it is larger than the sum of its proper divisors (1).
13921596912277 is an equidigital number, since it uses as much as digits as its factorization.
13921596912277 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25719120, while the sum is 64.
The spelling of 13921596912277 in words is "thirteen trillion, nine hundred twenty-one billion, five hundred ninety-six million, nine hundred twelve thousand, two hundred seventy-seven".
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