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1394259314317 is a prime number
BaseRepresentation
bin10100010010100000010…
…101001100011010001101
311221021211022212202011121
4110102200111030122031
5140320420341024232
62544302555520541
7202506021426052
oct24224025143215
94837738782147
101394259314317
11498336042161
121a6272759151
13a162a49223c
144b6a801d029
152640419ad97
hex144a054c68d

1394259314317 has 2 divisors, whose sum is σ = 1394259314318. Its totient is φ = 1394259314316.

The previous prime is 1394259314309. The next prime is 1394259314321. The reversal of 1394259314317 is 7134139524931.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1393979287561 + 280026756 = 1180669^2 + 16734^2 .

It is an emirp because it is prime and its reverse (7134139524931) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1394259314317 - 23 = 1394259314309 is a prime.

It is a super-2 number, since 2×13942593143172 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1394259314717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 697129657158 + 697129657159.

It is an arithmetic number, because the mean of its divisors is an integer number (697129657159).

Almost surely, 21394259314317 is an apocalyptic number.

It is an amenable number.

1394259314317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1394259314317 is an equidigital number, since it uses as much as digits as its factorization.

1394259314317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2449440, while the sum is 52.

The spelling of 1394259314317 in words is "one trillion, three hundred ninety-four billion, two hundred fifty-nine million, three hundred fourteen thousand, three hundred seventeen".