13950110437 has 4 divisors (see below), whose sum is σ = 14011564896. Its totient is φ = 13888655980.

The previous prime is 13950110431. The next prime is 13950110491. The reversal of 13950110437 is 73401105931.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 73401105931 = 53 ⋅1384926527.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13950110437 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13950110431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30726889 + ... + 30727342.

It is an arithmetic number, because the mean of its divisors is an integer number (3502891224).

Almost surely, 2^13950110437 is an apocalyptic number.

It is an amenable number.

13950110437 is a deficient number, since it is larger than the sum of its proper divisors (61454459).

13950110437 is an equidigital number, since it uses as much as digits as its factorization.

13950110437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61454458.

The product of its (nonzero) digits is 11340, while the sum is 34.

The spelling of 13950110437 in words is "thirteen billion, nine hundred fifty million, one hundred ten thousand, four hundred thirty-seven".