Base | Representation |
---|---|
bin | 1100101100001101000001… |
… | …0110100010110011110011 |
3 | 1211101221112211211100101002 |
4 | 3023003100112202303303 |
5 | 3312103332113114313 |
6 | 45402101100232215 |
7 | 2640052650335312 |
oct | 313032026426363 |
9 | 54357484740332 |
10 | 13953549348083 |
11 | 449a737925364 |
12 | 169435b53b66b |
13 | 7a2a7763b2b7 |
14 | 3634d92a4279 |
15 | 192e6ce62058 |
hex | cb0d05a2cf3 |
13953549348083 has 2 divisors, whose sum is σ = 13953549348084. Its totient is φ = 13953549348082.
The previous prime is 13953549347993. The next prime is 13953549348091. The reversal of 13953549348083 is 38084394535931.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13953549348083 - 238 = 13678671441139 is a prime.
It is not a weakly prime, because it can be changed into another prime (13953549398083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6976774674041 + 6976774674042.
It is an arithmetic number, because the mean of its divisors is an integer number (6976774674042).
Almost surely, 213953549348083 is an apocalyptic number.
13953549348083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13953549348083 is an equidigital number, since it uses as much as digits as its factorization.
13953549348083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 167961600, while the sum is 65.
The spelling of 13953549348083 in words is "thirteen trillion, nine hundred fifty-three billion, five hundred forty-nine million, three hundred forty-eight thousand, eighty-three".
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