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13953549348091 is a prime number
BaseRepresentation
bin1100101100001101000001…
…0110100010110011111011
31211101221112211211100101101
43023003100112202303323
53312103332113114331
645402101100232231
72640052650335323
oct313032026426373
954357484740341
1013953549348091
11449a737925371
12169435b53b677
137a2a7763b2c2
143634d92a4283
15192e6ce62061
hexcb0d05a2cfb

13953549348091 has 2 divisors, whose sum is σ = 13953549348092. Its totient is φ = 13953549348090.

The previous prime is 13953549348083. The next prime is 13953549348107. The reversal of 13953549348091 is 19084394535931.

13953549348091 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13953549348091 - 23 = 13953549348083 is a prime.

It is a super-2 number, since 2×139535493480912 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13953549348691) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6976774674045 + 6976774674046.

It is an arithmetic number, because the mean of its divisors is an integer number (6976774674046).

Almost surely, 213953549348091 is an apocalyptic number.

13953549348091 is a deficient number, since it is larger than the sum of its proper divisors (1).

13953549348091 is an equidigital number, since it uses as much as digits as its factorization.

13953549348091 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62985600, while the sum is 64.

The spelling of 13953549348091 in words is "thirteen trillion, nine hundred fifty-three billion, five hundred forty-nine million, three hundred forty-eight thousand, ninety-one".