13958112740051 has 2 divisors, whose sum is σ = 13958112740052. Its totient is φ = 13958112740050.

The previous prime is 13958112740029. The next prime is 13958112740119. The reversal of 13958112740051 is 15004721185931.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13958112740051 is a prime.

It is a super-2 number, since 2×13958112740051² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13958112739978 and 13958112740005.

It is not a weakly prime, because it can be changed into another prime (13958112745051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6979056370025 + 6979056370026.

It is an arithmetic number, because the mean of its divisors is an integer number (6979056370026).

Almost surely, 2^{13958112740051} is an apocalyptic number.

13958112740051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13958112740051 is an equidigital number, since it uses as much as digits as its factorization.

13958112740051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 47.

The spelling of 13958112740051 in words is "thirteen trillion, nine hundred fifty-eight billion, one hundred twelve million, seven hundred forty thousand, fifty-one".