Base | Representation |
---|---|
bin | 1100101100011110000001… |
… | …0110100000001100010111 |
3 | 1211102101022212122200101221 |
4 | 3023013200112200030113 |
5 | 3312142203330140434 |
6 | 45404133553431211 |
7 | 2640304021461262 |
oct | 313074026401427 |
9 | 54371285580357 |
10 | 13958112740119 |
11 | 44a1669833339 |
12 | 169521386b507 |
13 | 7a3323bab982 |
14 | 36380d391cd9 |
15 | 1931388c32b4 |
hex | cb1e05a0317 |
13958112740119 has 2 divisors, whose sum is σ = 13958112740120. Its totient is φ = 13958112740118.
The previous prime is 13958112740051. The next prime is 13958112740129. The reversal of 13958112740119 is 91104721185931.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13958112740119 - 211 = 13958112738071 is a prime.
It is a super-2 number, since 2×139581127401192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13958112740129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6979056370059 + 6979056370060.
It is an arithmetic number, because the mean of its divisors is an integer number (6979056370060).
Almost surely, 213958112740119 is an apocalyptic number.
13958112740119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13958112740119 is an equidigital number, since it uses as much as digits as its factorization.
13958112740119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 52.
The spelling of 13958112740119 in words is "thirteen trillion, nine hundred fifty-eight billion, one hundred twelve million, seven hundred forty thousand, one hundred nineteen".
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