Base | Representation |
---|---|
bin | 10100010100011110111… |
… | …111101010001110100101 |
3 | 11221111022102120001101101 |
4 | 110110132333222032211 |
5 | 140334243400010332 |
6 | 2545253511200101 |
7 | 202612464232252 |
oct | 24243677521645 |
9 | 4844272501341 |
10 | 1396384375717 |
11 | 499226638251 |
12 | 1a6766376031 |
13 | a18a8816216 |
14 | 4b82a350429 |
15 | 264caa13ae7 |
hex | 1451efea3a5 |
1396384375717 has 2 divisors, whose sum is σ = 1396384375718. Its totient is φ = 1396384375716.
The previous prime is 1396384375679. The next prime is 1396384375741. The reversal of 1396384375717 is 7175734836931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 909412084161 + 486972291556 = 953631^2 + 697834^2 .
It is a cyclic number.
It is not a de Polignac number, because 1396384375717 - 223 = 1396375987109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1396384375777) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 698192187858 + 698192187859.
It is an arithmetic number, because the mean of its divisors is an integer number (698192187859).
Almost surely, 21396384375717 is an apocalyptic number.
It is an amenable number.
1396384375717 is a deficient number, since it is larger than the sum of its proper divisors (1).
1396384375717 is an equidigital number, since it uses as much as digits as its factorization.
1396384375717 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 80015040, while the sum is 64.
The spelling of 1396384375717 in words is "one trillion, three hundred ninety-six billion, three hundred eighty-four million, three hundred seventy-five thousand, seven hundred seventeen".
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