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139910011 is a prime number
BaseRepresentation
bin10000101011011…
…01101101111011
3100202021011110021
420111231231323
5241304110021
621514431311
73316133623
oct1025555573
9322234407
10139910011
1171a8050a
123aa32537
1322ca83b7
141481d883
15c439c41
hex856db7b

139910011 has 2 divisors, whose sum is σ = 139910012. Its totient is φ = 139910010.

The previous prime is 139910009. The next prime is 139910021. The reversal of 139910011 is 110019931.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 139910011 - 21 = 139910009 is a prime.

It is a super-2 number, since 2×1399100112 = 39149622356040242, which contains 22 as substring.

Together with 139910009, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (139910021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69955005 + 69955006.

It is an arithmetic number, because the mean of its divisors is an integer number (69955006).

Almost surely, 2139910011 is an apocalyptic number.

139910011 is a deficient number, since it is larger than the sum of its proper divisors (1).

139910011 is an equidigital number, since it uses as much as digits as its factorization.

139910011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 25.

The square root of 139910011 is about 11828.3562256131. The cubic root of 139910011 is about 519.1381322080.

Adding to 139910011 its reverse (110019931), we get a palindrome (249929942).

The spelling of 139910011 in words is "one hundred thirty-nine million, nine hundred ten thousand, eleven".