Base | Representation |
---|---|
bin | 11010000011111110… |
… | …11100001100011111 |
3 | 1100010010111212021011 |
4 | 31001333130030133 |
5 | 212123431121422 |
6 | 10232230120051 |
7 | 1003510322011 |
oct | 150177341437 |
9 | 40103455234 |
10 | 13992051487 |
11 | 5a3016a417 |
12 | 2865ab0027 |
13 | 141ca8800b |
14 | 96a4081b1 |
15 | 56d5b3077 |
hex | 341fdc31f |
13992051487 has 2 divisors, whose sum is σ = 13992051488. Its totient is φ = 13992051486.
The previous prime is 13992051419. The next prime is 13992051511. The reversal of 13992051487 is 78415029931.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13992051487 - 223 = 13983662879 is a prime.
It is a super-2 number, since 2×139920514872 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13992051487.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13993051487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6996025743 + 6996025744.
It is an arithmetic number, because the mean of its divisors is an integer number (6996025744).
Almost surely, 213992051487 is an apocalyptic number.
13992051487 is a deficient number, since it is larger than the sum of its proper divisors (1).
13992051487 is an equidigital number, since it uses as much as digits as its factorization.
13992051487 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 49.
The spelling of 13992051487 in words is "thirteen billion, nine hundred ninety-two million, fifty-one thousand, four hundred eighty-seven".
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