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13999044583 is a prime number
BaseRepresentation
bin11010000100110100…
…00111011111100111
31100010121200010222201
431002122013133213
5212132223411313
610233040035331
71003623626026
oct150232073747
940117603881
1013999044583
115a34106437
122868302b47
131421366044
1496b3088bd
1556dee50dd
hex3426877e7

13999044583 has 2 divisors, whose sum is σ = 13999044584. Its totient is φ = 13999044582.

The previous prime is 13999044533. The next prime is 13999044607. The reversal of 13999044583 is 38544099931.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13999044583 - 233 = 5409109991 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13999044533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6999522291 + 6999522292.

It is an arithmetic number, because the mean of its divisors is an integer number (6999522292).

Almost surely, 213999044583 is an apocalyptic number.

13999044583 is a deficient number, since it is larger than the sum of its proper divisors (1).

13999044583 is an equidigital number, since it uses as much as digits as its factorization.

13999044583 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4199040, while the sum is 55.

The spelling of 13999044583 in words is "thirteen billion, nine hundred ninety-nine million, forty-four thousand, five hundred eighty-three".