Base | Representation |
---|---|
bin | 10100010111110110100… |
… | …101000010101010000111 |
3 | 11221211122111101122120112 |
4 | 110113312211002222013 |
5 | 140414200311322201 |
6 | 2551052434023235 |
7 | 203101223334533 |
oct | 24276645025207 |
9 | 4854574348515 |
10 | 1400001276551 |
11 | 49a81224a399 |
12 | 1a73b5717b1b |
13 | a2033c62c27 |
14 | 4ba9085cbc3 |
15 | 2663d3130bb |
hex | 145f6942a87 |
1400001276551 has 2 divisors, whose sum is σ = 1400001276552. Its totient is φ = 1400001276550.
The previous prime is 1400001276463. The next prime is 1400001276601. The reversal of 1400001276551 is 1556721000041.
It is a strong prime.
It is an emirp because it is prime and its reverse (1556721000041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1400001276551 - 230 = 1398927534727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400001276251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700000638275 + 700000638276.
It is an arithmetic number, because the mean of its divisors is an integer number (700000638276).
Almost surely, 21400001276551 is an apocalyptic number.
1400001276551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400001276551 is an equidigital number, since it uses as much as digits as its factorization.
1400001276551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 32.
Adding to 1400001276551 its reverse (1556721000041), we get a palindrome (2956722276592).
The spelling of 1400001276551 in words is "one trillion, four hundred billion, one million, two hundred seventy-six thousand, five hundred fifty-one".
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