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1400016356143 is a prime number
BaseRepresentation
bin10100010111110111011…
…110100100001100101111
311221211200112202202212221
4110113313132210030233
5140414213141344033
62551054133140211
7203101465451416
oct24276736441457
94854615682787
101400016356143
1149a81a809969
121a73ba78a667
13a2037112872
144ba9286647d
152663e7e112d
hex145f77a432f

1400016356143 has 2 divisors, whose sum is σ = 1400016356144. Its totient is φ = 1400016356142.

The previous prime is 1400016356131. The next prime is 1400016356149. The reversal of 1400016356143 is 3416536100041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1400016356143 is a prime.

It is a super-3 number, since 3×14000163561433 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1400016356099 and 1400016356108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1400016356149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700008178071 + 700008178072.

It is an arithmetic number, because the mean of its divisors is an integer number (700008178072).

Almost surely, 21400016356143 is an apocalyptic number.

1400016356143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400016356143 is an equidigital number, since it uses as much as digits as its factorization.

1400016356143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 34.

The spelling of 1400016356143 in words is "one trillion, four hundred billion, sixteen million, three hundred fifty-six thousand, one hundred forty-three".