Base | Representation |
---|---|
bin | 10100010111110111011… |
… | …110100100001100101111 |
3 | 11221211200112202202212221 |
4 | 110113313132210030233 |
5 | 140414213141344033 |
6 | 2551054133140211 |
7 | 203101465451416 |
oct | 24276736441457 |
9 | 4854615682787 |
10 | 1400016356143 |
11 | 49a81a809969 |
12 | 1a73ba78a667 |
13 | a2037112872 |
14 | 4ba9286647d |
15 | 2663e7e112d |
hex | 145f77a432f |
1400016356143 has 2 divisors, whose sum is σ = 1400016356144. Its totient is φ = 1400016356142.
The previous prime is 1400016356131. The next prime is 1400016356149. The reversal of 1400016356143 is 3416536100041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1400016356143 is a prime.
It is a super-3 number, since 3×14000163561433 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1400016356099 and 1400016356108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400016356149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700008178071 + 700008178072.
It is an arithmetic number, because the mean of its divisors is an integer number (700008178072).
Almost surely, 21400016356143 is an apocalyptic number.
1400016356143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400016356143 is an equidigital number, since it uses as much as digits as its factorization.
1400016356143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 34.
The spelling of 1400016356143 in words is "one trillion, four hundred billion, sixteen million, three hundred fifty-six thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •