140004341021 has 2 divisors, whose sum is σ = 140004341022. Its totient is φ = 140004341020.

The previous prime is 140004340979. The next prime is 140004341023. The reversal of 140004341021 is 120143400041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136186831225 + 3817509796 = 369035^2 + 61786^2 .

It is a cyclic number.

It is not a de Polignac number, because 140004341021 - 2¹⁴ = 140004324637 is a prime.

Together with 140004341023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 140004340984 and 140004341002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140004341023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70002170510 + 70002170511.

It is an arithmetic number, because the mean of its divisors is an integer number (70002170511).

Almost surely, 2^140004341021 is an apocalyptic number.

It is an amenable number.

140004341021 is a deficient number, since it is larger than the sum of its proper divisors (1).

140004341021 is an equidigital number, since it uses as much as digits as its factorization.

140004341021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 140004341021 its reverse (120143400041), we get a palindrome (260147741062).

The spelling of 140004341021 in words is "one hundred forty billion, four million, three hundred forty-one thousand, twenty-one".