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14000440040701 is a prime number
BaseRepresentation
bin1100101110111011101101…
…0000010101110011111101
31211120102120201221100010021
43023232323100111303331
53313340400122300301
645435414030412141
72643332645550052
oct313567320256375
954512521840107
1014000440040701
11450860a459794
1216a1467061051
137a730b17476a
143658a6a97029
151942b48708a1
hexcbbbb415cfd

14000440040701 has 2 divisors, whose sum is σ = 14000440040702. Its totient is φ = 14000440040700.

The previous prime is 14000440040659. The next prime is 14000440040723. The reversal of 14000440040701 is 10704004400041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12688029224676 + 1312410816025 = 3562026^2 + 1145605^2 .

It is a cyclic number.

It is not a de Polignac number, because 14000440040701 - 221 = 14000437943549 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14000440040731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000220020350 + 7000220020351.

It is an arithmetic number, because the mean of its divisors is an integer number (7000220020351).

Almost surely, 214000440040701 is an apocalyptic number.

It is an amenable number.

14000440040701 is a deficient number, since it is larger than the sum of its proper divisors (1).

14000440040701 is an equidigital number, since it uses as much as digits as its factorization.

14000440040701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1792, while the sum is 25.

Adding to 14000440040701 its reverse (10704004400041), we get a palindrome (24704444440742).

The spelling of 14000440040701 in words is "fourteen trillion, four hundred forty million, forty thousand, seven hundred one".