Base | Representation |
---|---|
bin | 11111110101011100010110… |
… | …111110101011101110110111 |
3 | 200100202000111201022000102221 |
4 | 133311130112332223232313 |
5 | 121322424111222204421 |
6 | 1213440345215543211 |
7 | 41330351326102054 |
oct | 3765342676535667 |
9 | 610660451260387 |
10 | 140012024413111 |
11 | 40680847747844 |
12 | 1385332782ab07 |
13 | 6018100942246 |
14 | 268089226202b |
15 | 112c079e80841 |
hex | 7f5716fabbb7 |
140012024413111 has 2 divisors, whose sum is σ = 140012024413112. Its totient is φ = 140012024413110.
The previous prime is 140012024413103. The next prime is 140012024413189. The reversal of 140012024413111 is 111314420210041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140012024413111 - 23 = 140012024413103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140012024113111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006012206555 + 70006012206556.
It is an arithmetic number, because the mean of its divisors is an integer number (70006012206556).
Almost surely, 2140012024413111 is an apocalyptic number.
140012024413111 is a deficient number, since it is larger than the sum of its proper divisors (1).
140012024413111 is an equidigital number, since it uses as much as digits as its factorization.
140012024413111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 140012024413111 its reverse (111314420210041), we get a palindrome (251326444623152).
The spelling of 140012024413111 in words is "one hundred forty trillion, twelve billion, twenty-four million, four hundred thirteen thousand, one hundred eleven".
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