Base | Representation |
---|---|
bin | 10100010111111101101… |
… | …011010100001000000000 |
3 | 11221211221210110210101011 |
4 | 110113331223110020000 |
5 | 140414421303031342 |
6 | 2551112330250304 |
7 | 203104200465100 |
oct | 24277553241000 |
9 | 4854853423334 |
10 | 1400120361472 |
11 | 49a873496688 |
12 | 1a7429586994 |
13 | a2052829491 |
14 | 4baa25bb200 |
15 | 266489d7717 |
hex | 145fdad4200 |
1400120361472 has 60 divisors (see below), whose sum is σ = 3254241863070. Its totient is φ = 600051572736.
The previous prime is 1400120361443. The next prime is 1400120361473. The reversal of 1400120361472 is 2741630210041.
It can be written as a sum of positive squares in only one way, i.e., 1071672166656 + 328448194816 = 1035216^2 + 573104^2 .
It is a super-3 number, since 3×14001203614723 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1400120361473) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 27879097 + ... + 27929272.
Almost surely, 21400120361472 is an apocalyptic number.
It is an amenable number.
1400120361472 is an abundant number, since it is smaller than the sum of its proper divisors (1854121501598).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1400120361472 is an frugal number, since it uses more digits than its factorization.
1400120361472 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55808401 (or 55808378 counting only the distinct ones).
The product of its (nonzero) digits is 8064, while the sum is 31.
The spelling of 1400120361472 in words is "one trillion, four hundred billion, one hundred twenty million, three hundred sixty-one thousand, four hundred seventy-two".
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