Base | Representation |
---|---|
bin | 11111110101011100010111… |
… | …111011000010000010011000 |
3 | 200100202000112211001202101220 |
4 | 133311130113323002002120 |
5 | 121322424124244424422 |
6 | 1213440350543012040 |
7 | 41330351610421365 |
oct | 3765342773020230 |
9 | 610660484052356 |
10 | 140012040233112 |
11 | 40680855672623 |
12 | 13853330b9a020 |
13 | 6018103cc0ba8 |
14 | 26808943bd46c |
15 | 112c07b557e5c |
hex | 7f5717ec2098 |
140012040233112 has 32 divisors (see below), whose sum is σ = 350030390437680. Its totient is φ = 46670641430400.
The previous prime is 140012040233081. The next prime is 140012040233113. The reversal of 140012040233112 is 211332040210041.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140012040233113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56164362 + ... + 58604262.
Almost surely, 2140012040233112 is an apocalyptic number.
140012040233112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
140012040233112 is an abundant number, since it is smaller than the sum of its proper divisors (210018350204568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140012040233112 is a wasteful number, since it uses less digits than its factorization.
140012040233112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4830923 (or 4830919 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 140012040233112 its reverse (211332040210041), we get a palindrome (351344080443153).
The spelling of 140012040233112 in words is "one hundred forty trillion, twelve billion, forty million, two hundred thirty-three thousand, one hundred twelve".
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