Base | Representation |
---|---|
bin | 1100101110111110100101… |
… | …0101110010010101110100 |
3 | 1211120111120121210221000110 |
4 | 3023233221111302111310 |
5 | 3313343441041021322 |
6 | 45440022450343020 |
7 | 2643361054506531 |
oct | 313575125622564 |
9 | 54514517727013 |
10 | 14001213220212 |
11 | 4508976940a19 |
12 | 16a1641b8aa70 |
13 | 7a74023c692a |
14 | 36593b63dd88 |
15 | 19430c69ac0c |
hex | cbbe9572574 |
14001213220212 has 12 divisors (see below), whose sum is σ = 32669497513856. Its totient is φ = 4667071073400.
The previous prime is 14001213220199. The next prime is 14001213220213. The reversal of 14001213220212 is 21202231210041.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (12).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14001213220213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 583383884164 + ... + 583383884187.
Almost surely, 214001213220212 is an apocalyptic number.
14001213220212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14001213220212 is an abundant number, since it is smaller than the sum of its proper divisors (18668284293644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14001213220212 is a wasteful number, since it uses less digits than its factorization.
14001213220212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1166767768358 (or 1166767768356 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 14001213220212 its reverse (21202231210041), we get a palindrome (35203444430253).
The spelling of 14001213220212 in words is "fourteen trillion, one billion, two hundred thirteen million, two hundred twenty thousand, two hundred twelve".
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